MathExprEquality(MathExpr, MathExpr) Operator

Creates a constraint expression where lhs = rhs.

Note that a constraint is composed of a constraint expression and forall sets expression.

C#
ConstraintExpr expr =             sum(over(j), x[i, j]) == sum(over(j), x[j, i]);
Constraint     con  = forall(i) | sum(over(j), x[i, j]) == sum(over(j), x[j, i]);

Definition

Namespace: Orx.MathProg
Assembly: Orx.MathProg (in Orx.MathProg.dll) Version: 1.0.0
C#
public static ConstraintExpr operator ==(
	MathExpr lhs,
	MathExpr rhs
)

Parameters

lhs  MathExpr
Lhs.
rhs  MathExpr
Rhs.

Return Value

ConstraintExpr

See Also